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C/C++ Users Group Library 1996 July
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cips1001.exe
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NUMCVRT.C
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1990-08-18
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/******************************************************
*
* file d:\cips\intcvrt.c
*
* Functions: This file contains
* get_integer
* int_convert
*
* Purpose: These functions convert a string of
* characters to their number value.
*
* Modifications:
* Taken from Jamsa's software package
* and altered to fit into the computer
* vision programming 22 August 1986.
*
*******************************************************/
#include "d:\cips\numdefs.h"
get_integer(n)
int *n;
{
char string[80];
read_string(string);
int_convert(string, n);
}
int_convert (ascii_val, result)
char *ascii_val;
int *result;
{
int sign = 1; /* -1 if negative */
*result = 0; /* value returned to the calling routine */
/* read passed blanks */
while (is_blank(*ascii_val))
ascii_val++; /* get next letter */
/* check for sign */
if (*ascii_val == '-' || *ascii_val == '+')
sign = (*ascii_val++ == '-') ? -1 : 1; /* find sign */
/*
* convert the ASCII representation to the actual
* decimal value by subtracting '0' from each character.
*
* for example, the ASCII '9' is equivalent to 57 in decimal.
* by subtracting '0' (or 48 in decimal) we get the desired
* value.
*
* if we have already converted '9' to 9 and the next character
* is '3', we must first multiply 9 by 10 and then convert '3'
* to decimal and add it to the previous total yielding 93.
*
*/
while (*ascii_val)
if (is_digit(*ascii_val))
*result = *result * 10 + to_decimal(*ascii_val++);
else
return (IO_ERROR);
*result = *result * sign;
return (NO_ERROR);
}
/************************************************
*
* Functions: This file contains
* get_short
* short_convert
*
* Purpose: These functions convert a string of
* characters to their number value.
*
* Modifications:
* Taken from Jamsa's software package
* and altered to fit into the computer
* vision programming 22 August 1986.
*
*************************************************/
get_short(n)
short *n;
{
char string[80];
read_string(string);
int_convert(string, n);
}
short_convert (ascii_val, result)
char *ascii_val;
short *result;
{
int sign = 1; /* -1 if negative */
*result = 0; /* value returned to the calling routine */
/* read passed blanks */
while (is_blank(*ascii_val))
ascii_val++; /* get next letter */
/* check for sign */
if (*ascii_val == '-' || *ascii_val == '+')
sign = (*ascii_val++ == '-') ? -1 : 1; /* find sign */
/*
* convert the ASCII representation to the actual
* decimal value by subtracting '0' from each character.
*
* for example, the ASCII '9' is equivalent to 57 in decimal.
* by subtracting '0' (or 48 in decimal) we get the desired
* value.
*
* if we have already converted '9' to 9 and the next character
* is '3', we must first multiply 9 by 10 and then convert '3'
* to decimal and add it to the previous total yielding 93.
*
*/
while (*ascii_val){
if (is_digit(*ascii_val)){
*result = *result * 10 + to_decimal(*ascii_val++);
if( (sign == -1) && (*result > 0)) *result = *result * -1;
}
else
return (IO_ERROR);
} /* ends while ascii_val */
return (NO_ERROR);
}
/***********************************************
*
* file d:\cips\locvrt.c
*
* Functions: This file contains
* get_long
* long_convert
*
* Purpose: These functions convert a string of
* characters to their number value.
*
* Modifications:
* Taken from Jamsa's software package
* and altered to fit into the computer
* vision programming 22 August 1986.
*
************************************************/
get_long(n)
long *n;
{
char string[80];
read_string(string);
long_convert(string, n);
}
long_convert (ascii_val, result)
char *ascii_val;
long *result;
{
int sign = 1; /* -1 if negative */
*result = 0; /* value returned to the calling routine */
/* read passed blanks */
while (is_blank(*ascii_val))
ascii_val++; /* get next letter */
/* check for sign */
if (*ascii_val == '-' || *ascii_val == '+')
sign = (*ascii_val++ == '-') ? -1 : 1; /* find sign */
/*
* convert the ASCII representation to the actual
* decimal value by subtracting '0' from each character.
*
* for example, the ASCII '9' is equivalent to 57 in decimal.
* by subtracting '0' (or 48 in decimal) we get the desired
* value.
*
* if we have already converted '9' to 9 and the next character
* is '3', we must first multiply 9 by 10 and then convert '3'
* to decimal and add it to the previous total yielding 93.
*
*/
while (*ascii_val)
if (is_digit(*ascii_val))
*result = *result * 10 + to_decimal(*ascii_val++);
else
return (IO_ERROR);
*result = *result * sign;
return (NO_ERROR);
}
/*******************************************************
*
* file d:\cips\flocvrt.c
*
* Functions: This file contains
* get_float
* float_convert
* power
*
* Purpose: This function converts a string of
* characters to its number value.
*
* Modifications:
* This was taken from Jamsa's software
* packages and modified to work in the
* computer vision programs 22 August 1986.
*
* 16 June 1987 - the power function was not working
* so Borland's Turbo C function pow10
* was substituted for it.
*
****************************************************/
get_float(f)
float *f;
{
char string[80];
read_string(string);
float_convert(string, f);
}
float_convert (ascii_val, result)
char *ascii_val;
float *result;
{
int count; /* # of digits to the right of the
decimal point. */
int sign = 1; /* -1 if negative */
double pow10(); /* Turbo C function */
float power(); /* function returning a value raised
to the power specified. */
*result = 0.0; /* value desired by the calling routine */
/* read passed blanks */
while (is_blank(*ascii_val))
ascii_val++; /* get the next letter */
/* check for a sign */
if (*ascii_val == '-' || *ascii_val == '+')
sign = (*ascii_val++ == '-') ? -1 : 1; /* find sign */
/*
* first convert the numbers on the left of the decimal point.
*
* if the number is 33.141592 this loop will convert 33
*
* convert ASCII representation to the actual decimal
* value by subtracting '0' from each character.
*
* for example, the ASCII '9' is equivalent to 57 in decimal.
* by subtracting '0' (or 48 in decimal) we get the desired
* value.
*
* if we have already converted '9' to 9 and the next character
* is '3', we must first multiply 9